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-936x^2+432x+2800=0
a = -936; b = 432; c = +2800;
Δ = b2-4ac
Δ = 4322-4·(-936)·2800
Δ = 10669824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10669824}=\sqrt{2304*4631}=\sqrt{2304}*\sqrt{4631}=48\sqrt{4631}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(432)-48\sqrt{4631}}{2*-936}=\frac{-432-48\sqrt{4631}}{-1872} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(432)+48\sqrt{4631}}{2*-936}=\frac{-432+48\sqrt{4631}}{-1872} $
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